Question

{Chance to earn 100 points!!!}

Create a function (using Python) to determine how much it'll cost for gas to drive to a destination with the following arguments:
-miles per gallon
-number of miles
-cost per gallon
Trip #1: You are driving from Winchester, VA to Pittsburgh, PA, which is about 190 miles. The cost of gas in PA is about $3.62/gallon. Your car gets about 25 mpg. Find the cost you'll pay for gas.
Trip #2: You are driving from Winchester, VA to Washington, DC which is about 75 miles. The cost of gas in Virginia is about $3.14/gallon. You decide to take your friend's car, which gets about 28 mpg. Find the cost you'll pay for gas.
Trip #3: You are driving from Winchester, VA to Myrtle Beach, SC which is about 460 miles. The cost of gas in North Carolina is about $3.12/gallon. You decide to take your mom's old van, which only gets about 20mpg. Find the cost you'll pay for gas.

Answer 1

def gasCost(MpG, numMiles, CpG):

# Figuring out number/gallons

totGallons = numMiles / MpG

# Finding cost

totCost = totGallons * CpG

# You can round up using the math module, but as you have not mentioned modules, I'll leave it in an unrounded state

return totCost

Step-by-step explanation:

Fairly simple stuff, though I chose not to round up, as that would need another module. You can use the function by putting it in a print statement and seeing what it'll return, E.G:

print(gasCost(25, 190, 3.52)

Answer 2

Here’s a Python function that calculates the cost of gas for a trip:

def calculate_gas_cost(mpg, miles, cost_per_gallon):

gallons = miles / mpg

cost = gallons * cost_per_gallon

return cost

For Trip #1, you would call the function like this:

calculate_gas_cost(25, 190, 3.62)

The cost of gas for this trip would be $27.56.

For Trip #2, you would call the function like this:

calculate_gas_cost(28, 75, 3.14)

The cost of gas for this trip would be $8.13.

For Trip #3, you would call the function like this:

calculate_gas_cost(20, 460, 3.12)

The cost of gas for this trip would be $86.88.

I hope this helps! Let me know if you have any other questions.