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If QV=3p–49, RU=p+27, and ST=p+39, what is the value of p?

If QV=3p–49, RU=p+27, and ST=p+39, what is the value of p?-example-1
User Gurudeb
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1 Answer

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Answer: p = 32

Explanation:

Assuming that QV is parallel to ST, we can use the midsegment theorem, which basically means that (QV + ST)/2 is RU.

From here you get the equation (3p - 49 + p + 39)/2 = p + 27

Then multiply both sides by 2, and combine like terms to get:

4p - 10 = 2p + 54

Further simplify:

2p = 64

p = 32.

User Loqman
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