Question

If a = 2 and b = 3, then the value of (a^b + b^a)-1 is :​

Answer 1

16

Explanation:

Given

(
`a^(b)` +
`b^(a)` ) - 1 ← substitute a = 2, b = 3

= (2³ + 3²) - 1

= (8 + 9) - 1

= 17 - 1

= 16

Answer 2

`16`

Explanation:

Substituting
`a=2` and
`b=3` into
`(a^(b)+b^(a))-1` gives us:

`(a^(b)+b^(a))-1`

`=(2^(3) +3^(2))-1` (Substitute given values into expression)

`=(8+9)-1` (Evaluate exponents)

`=17-1` (Evaluate expression in parentheses)

`=16` (Simplify)

Hope this helps!