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Ruhama scores 75, 80, 85 and x in four subjects. For what value of x, Ruhama's average is less than 80? ​

User Jaymee
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2 Answers

2 votes
Answer:

x < 80

Step by step explanation:

To find the value of x for which Ruhama's average is less than 80, we need to use the formula for calculating the average or arithmetic mean:

Average = (sum of all scores) / (number of scores)

In this case, we have the sum of Ruhama's scores in three subjects, which is:

75 + 80 + 85 = 240

We also know that Ruhama has four scores in total. Therefore, we can express the formula for the average as:

Average = (240 + x) / 4

To find the value of x for which Ruhama's average is less than 80, we can set up the following inequality:

(240 + x) / 4 < 80

Simplifying this inequality, we get:

240 + x < 320

Subtracting 240 from both sides, we get:

x < 80

Therefore, for Ruhama's average to be less than 80, the value of x must be less than 80.
User Thispatchofsky
by
7.4k points
1 vote

Answer:

Therefore, for Ruhama's average to be less than 80, the value of x must be less than 80.

Explanation:

Let's use the formula for the average (or mean) of a set of numbers: average = (sum of numbers) / (number of numbers)

To find the value of x that makes Ruhama's average less than 80, we need to solve the following inequality:

(75 + 80 + 85 + x) / 4 < 80

Multiplying both sides by 4 gives:

75 + 80 + 85 + x < 320

Simplifying:

x < 320 - 75 - 80 - 85 x < 80

User Bsofman
by
8.0k points

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