Question

The means of six number = 41

Three numbers are 32 , 31 , 42

other three are a,a,a

What sum of 6 numbers

find value of A?

Answer 1

`\qquad\huge \rm༆ Answer ༄`

Let's use the formula to fund mean here ~

`\boxed{ \sf mean = (sum \: of \: all \: terms)/(number \: of \: terms) }`

That is ;

`\qquad \sf  \dashrightarrow \: 41 = (32 + 31 + 42 + a + a + a)/(6)`

`\qquad \sf  \dashrightarrow \: (41 * 6) = 105 + 3a`

`\qquad \sf  \dashrightarrow \: 246 = 105 + 3a`

`\qquad \sf  \dashrightarrow \: 3a = 246 - 105`

`\qquad \sf  \dashrightarrow \: 3a = 141`

`\qquad \sf  \dashrightarrow \: a = 141 / 3`

`\qquad \sf  \dashrightarrow \: a = 47`

Therefore the value of a is 47