Question

An object is dropped from a bridge. A second object is thrown downwards 1.0 s later. They both reach the water 20 m below at the same instant. What was the initial speed of the second object? Neglect air resistance.

Answer 1

15m/s

Step-by-step explanation:

`20m = (1)/(2) g {t}^(2) \\ t = 2s \\ t0 = 2s - 1s = 1s \\ vt + (1)/(2) g {t}^(2) = 20m \\ v * 1s + (1)/(2) * 10 * 1 = 20 \\ v = 15`