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Mike's car holds 14 2/5 g of gas, averages 20mpg. About how far can Mike's travel if his tank is 1/4 full?

User Andy Rose
by
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1 Answer

6 votes

Solution :

It is given that :

The car of Mike's can hold =
$14 (2)/(5)$ g of gas.


$=(72)/(5)$ g of gas


$=(1)/(4) $ th of
$(72)/(5)$ g of gas is
$=(1)/(4) * (72)/(5)$


$=(18)/(5)$ g of gas

The average distance that the car can travel when the tank is full is = 20 mpg

∴ In
$(72)/(5)$ g of gas, the car travels = 20 mpg

In 1 g of gas, the car travels =
$20 * (5)/(72) $ mpg

So in
$(18)/(5)$ g of gas, the car travels =
$20 * (5)/(72) * (18)/(5) $ mpg

= 5 mpg

User Mherzog
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4.7k points