Question

Helen plays basketball. For free throws, she makes the shot 75% of the time. Helen must now attempt two free throws. The probability that Helen makes the second free throw given that she made the first is 0.85. What is the probability that she makes both free throws?

Answer 1

Answer: 0.6375

Explanation:

Let's assume that the event that she'll make the first shot is given as P(A) while making the second shot is P(B). Therefore, P(A/B) = 0.85

Therefore, the probability that she makes both free throws will be denoted as:

= 0.75 × 0.85

= 0.6375