Question

If 0.296J of heat causes a 0.661°C temperature change, what mass of water is present?

A) 0.045 g
B) 0.099 g
C) 0.294 g
D) 0.661 g

Answer 1

To calculate the mass of water present, use the equation Q = mcΔT and rearrange for m. The mass of water present is 0.045 g.

Step-by-step explanation:

To calculate the mass of water present, we can use the equation Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the temperature change.

Given that Q = 0.296J, ΔT = 0.661°C, and c = 4.184J/g°C for water, we can rearrange the equation to solve for m: m = Q / (cΔT).

Plugging in the values, we get m = 0.296J / (4.184J/g°C * 0.661°C) = 0.045 g.

Therefore, the mass of water present is 0.045 g.