Question

I need an explanation for the problem 4v2=-12v-9. I don't understand why it factors into 4v+3 and 4v+3

Answer 1

The factors are
`2v+3,2v+3`.

The factors are not
`4v+3,4v+3`

Explanation:

Equation is
`4v^2=-12v-9`.

This equation can be written as follows:

`4v^2+12v+9=0`

Here,

`12v=6v+6v`

Therefore,

`4v^2+6v+6v+9=0\\2v(2v+3)+3(2v+3)=0\\(2v+3)(2v+3)=0`

So, the factors are
`2v+3,2v+3`.

The factors are not
`4v+3,4v+3`