Question

What is 2/3 (6x - 1/6) + 3x?​

Answer 1

`= \tt (2)/(3) (6x - (1)/(6) ) + 3x`

`=\tt (2)/(3) * 6x - (2)/(3) * (1)/(6) + 3x`

`=\tt (2 * 6)/(3)x - (2 * 1)/(3 * 6) + 3x`

`= \tt (12)/(3) x - (2)/(18) + 3x`

`=\tt 4x - (2 / 2)/(18 / 2) + 3x`

`= \tt4 x- (1)/(9) + 3x`

`= \tt4x + 3x - (1)/(9)`

`\color{plum}= \tt\bold{7x - (1)/(9) }`

Therefore,

`\color{hotpink}\tt (2)/(3) (6x - (1)/(6) ) + 3x \color{plm}= \color{plum}\tt\bold{7x - (1)/(9) }`

Answer 2

answer::

7x=-1/9!!!!!