Question

Una pelota de golf se suelta desde el reposo del techo de un edificio muy alto. Despreciando la resistencia del aire, calcule (a) la posicion y (b) la velocidad de la pelota despues de 1s, 2s y 3s.

Answer 1

a) y = y₀ - 4.9, v = -9.8 m / s, b) y =y₀ - 19.6, v = - 19 m / s

c) y =y₀ - 44.1, v = - 29.4 m / s

Step-by-step explanation:

To solve this exercise let us use the kinematic relations

y =y₀ + v₀ t - ½ g t²

v = v₀ - g t

They indicate that the body is released therefore the initial velocity is zero v₀ = 0

y = y₀ - ½ g t²

v = - gt

a) the position and velocity for t = 1s

y = y₀ - ½ 9.8 12

y = y₀ - 4.9

v = - 9.8 1

v = -9.8 m / s

the negative sign indicates that the velocity is directed downwards

b) t = 2 s

y =y₀ - ½ 9.8 2 2

y =y₀ - 19.6

v = - 9.8 2

v = - 19 m / s

c) t = 3 s

y = y₀ - ½ 9.8 3 2

y =y₀ - 44.1

v = - 9.8 3

v = - 29.4 m / s