Question

A projectile fired from a gun has initial horizontal and vertical components of velocity equal to 30 m/s and 40 m/s. At what angle is the projectile fired?

A) 37
B) 40
C) 45
D) 53
E) 60

Answer 1

The projectile is fired at an angle of approximately 53 degrees.

Step-by-step explanation:

To find the angle at which the projectile is fired, we can use trigonometry. The horizontal component of velocity can be represented by the equation vx = v * cos(θ), where v is the initial velocity and θ is the angle. The vertical component of velocity can be represented by the equation vy = v * sin(θ). Given that vx = 30 m/s and vy = 40 m/s, we can solve for θ using the equation tan(θ) = vy / vx. Plugging in the given values, we get tan(θ) = 40 / 30, which simplifies to θ = atan(40 / 30). Using a calculator or a trigonometric table, we find that θ = 53.13 degrees. Therefore, the projectile is fired at an angle of approximately 53 degrees.