Question

Calculate the gravitational potential energy for a cat (4.0 kg) lifted 0.95 m above the ground. It should be two answer .

Answer 1

U=37.24J

Step-by-step explanation:

I don't know what the two answers would be, but the gravitational potential energy can be found with
`U=mgh` where

m= mass in kg

g= gravity in
`(m)/(s^2)`

h= height in m

For this problem, let

m= 4.0 kg

g= 9.8
`(m)/(s^2)`

h= 0.95 m

So,

`U=mgh\\U=(4.0kg)(9.8(m)/(s^2))(0.95m)\\U=37.24(kg*m^2)/(s^2)`

Recall that
`(kg*m^2)/(s^2)` is equal to 1 Joule. So,

U= 37.24J