Question

8. Tom leaves for Los Angeles averaging 65 mi/h. Michelle leaves for Lo

Angeles one hour later than Tom from the same location. She travels
the same route averaging 70 mi/h. When will she pass Tom?

Can someone solve this for me by using systems. I’m kinda confused. Ty

Answer 1

If Tom leaves for Los Angeles averaging 65 mi/h, he will travel 65 x 1 = <<65*1=65>>65 miles in 1 hour.

If Michelle leaves for Los Angeles one hour later than Tom, traveling the same route at an average speed of 70 mi/h, she will travel 70 x 1 = <<70*1=70>>70 miles in 1 hour.

Since Michelle is traveling at a faster speed than Tom, she will catch up to Tom after traveling 70 - 65 = <<70-65=5>>5 miles.

Therefore, Michelle will pass Tom after traveling for 5 / (70 - 65) = <<5/(70-65)=1>>1 hour.

Explanation: