Final answer:
The axis of symmetry of the function f(x) = 2(x+3)^2 - 4 is x = -3, which is the vertical line that passes through the vertex of the parabola, located at (-3, -4).
Step-by-step explanation:
To find the axis of symmetry of the function f(x) = 2(x+3)^2 - 4, we need to identify the vertex form of a quadratic function, which is generally given as f(x) = a(x-h)^2 + k, where (h, k) is the vertex of the parabola.
In the function provided, h = -3 and k = -4, which means the vertex of the parabola is at (-3, -4).
Therefore, the axis of symmetry is the vertical line that passes through the vertex; for this function, the axis of symmetry is x = -3.