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What is the maximum capacity of 100 feet (30,480 mm) of 1-inch (25 mm) semi-rigid copper tubing conveying natural gas pressure of 5.0 psi (34 KPa) and a design pressure drop of 3.5 psi (24 KPa)?

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Final answer:

The maximum capacity of 100 feet (30,480 mm) of 1-inch (25 mm) semi-rigid copper tubing can be calculated using the formula for flow rate, which is Q = (πd²/4)v, where Q is the flow rate, d is the diameter, and v is the velocity of the fluid.

Step-by-step explanation:

The maximum capacity of the 100 feet (30,480 mm) of 1-inch (25 mm) semi-rigid copper tubing can be calculated using the formula for flow rate, which is given by Q = (πd²/4)v, where Q is the flow rate, d is the diameter, and v is the velocity of the fluid.

To calculate the flow rate, we first need to convert the diameter of the tubing and the pressure drop into the corresponding SI units. The diameter of the tubing is 25 mm, which is equivalent to 0.025 m, and the pressure drop is 3.5 psi, which is equivalent to 24 KPa.

By assuming incompressible flow, we can calculate the flow rate using the equation Q = A * v, where A is the cross-sectional area of the tubing and v is the velocity of the fluid. The cross-sectional area of the tubing can be calculated using the formula A = π * r², where r is the radius of the tubing.

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