Final answer:
The maximum total quantity of dry aggregate for M15 grade concrete is calculated based on the ratio of cement, fine aggregate, and coarse aggregate. Option A is correct.
Step-by-step explanation:
In M15 grade concrete, the maximum total quantity of dry aggregate by mass per 50 kg of symmetric why is determined by the sum of individual masses of fine aggregate and coarse aggregate.
For M15 grade concrete, the ratio of cement: fine aggregate: coarse aggregate is 1:2:4.
Hence, the maximum total quantity of dry aggregate can be calculated as follows:
Total quantity of dry aggregate = (2/7) x 50 kg = 14.29 kg
Therefore, the correct answer is option a. 625.
The student is asking about the maximum total quantity of dry aggregate by mass required for M15 grade concrete in relation to a 50 kg bag of cement. In concrete mix design, particularly as per IS 10262 (2009) for M15 grade concrete, the standard proportion is 1:2:4 (cement: fine aggregate: coarse aggregate). The quantity of water typically used is around 55% of the cement weight.
Generally, for M15 concrete, the total quantity of dry aggregates required is approximately 2 to 2.5 times the weight of the cement. Therefore, if we have a 50 kg bag of cement, the total dry aggregates' weight would be about 100 to 125 kg. However, as per Indian Standard recommendations, to ensure the workability and strength of the concrete, a specific maximum quantity of aggregates by mass per 50 kg of cement shall be adhered to.