Question

A plate has an area of 1m square. It slide down an incline plane , having an angle of inclined 60° to horizontal, which a velocity of 0.75m/s. The thickness of oil film between the plate and the plate is 2mm. Find the viscosity of the fluid if the weight of the plate is 90N

Answer 1

`\mu =0.169704 Ns/m^2`

Step-by-step explanation:

From the question we are told that

Area of plate
`a=1m^2`

Angle of inclination
`\theta=60 \textdegree`

Velocity
`v=0.75m/s`

Thickness of oil
`t=2mm`

Weight of plate
`w=90N`

Generally the equation for shear force is mathematically given by

`F=mgsin45 \textdegree`

`F=90sin45 \textdegree`

`F=63.639N`

`F=\mu* (v)/(t)`

`F=\mu* (0.75)/(2*10^-^3)`

`\mu* (0.75)/(2*10^-^3)=63.639N`

`\mu =(63.639)/(375)`

Therefore viscosity is given by

`\mu =0.169704 Ns/m^2`