Final answer:
Pb(IO₃)₂ is correctly named as lead(II) iodate, reflecting the +2 charge on the lead ion.
Step-by-step explanation:
The compound Pb(IO₃)₂ should be named according to the rules of nomenclature for ionic compounds that contain a metal with a variable charge and a polyatomic ion. Here, Pb represents lead, and IO₃ is the polyatomic ion iodate. In lead iodate, lead has a charge of +2, which we can deduce based on the charge of the iodate ion (IO₃)⁻ which has a -1 charge, and there are two of them, summing up to -2. This requires that lead has a +2 charge to neutralize the compound. Therefore, the correct name is lead(II) iodate.