Question

What is returned by the call go( 5.0 ) ?

public static double go( double w )
{
while(w > 0)
{
w = w - 0.75;
}
return w;
}

Answer 1

The call go( 5.0 ) returns 0.25. The final value of 'w' when the loop terminates is 0.25, which is then returned as the output of the function go( 5.0 ).

Step-by-step explanation:

The function go( double w ) uses a while loop to decrement the value of the input 'w' by 0.75 until 'w' becomes less than or equal to 0. When the loop exits, the final value of 'w' is returned. Starting with 5.0, the loop subtracts 0.75 from 'w' repeatedly until 'w' is no longer greater than 0. After four iterations, 'w' becomes 0.25, which is less than 0. Therefore, the loop stops, and the value 0.25 is returned as the final result.

This code demonstrates a typical loop operation where a value is decremented by a fixed amount until a certain condition is met. In this case, the loop continues until 'w' is no longer greater than 0. Each iteration reduces 'w' by 0.75 until it reaches a point where subtracting 0.75 makes 'w' less than or equal to 0. The final value of 'w' when the loop terminates is 0.25, which is then returned as the output of the function go( 5.0 ).

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