Question

A cyclist accelerates from 0 m/s to 8 m/s in 3 seconds. What is her acceleration? Is the acceleration higher of another cyclist who accelerates from 0 to 30 m/s in 8 seconds? How do you know?

Answer 1

Acceleration of one cyclist=
`2.67m/s^2`

Yes, the acceleration is higher of another cyclist who accelerates from 0 to 30 m/s in 8 seconds.

Step-by-step explanation:

We are given that

Initial velocity of one cyclist, u=0 m/s

Final velocity of one cyclist, v=8m/s

Time, t=3 s

Initial velocity of another cyclist, u'=0

Final velocity of another cyclist, v'=30m/s

Time, t'=8 s

We know that

Acceleration,
`a=(v-u)/(t)`

Using the formula

`a=(8-0)/(3)=(8)/(3)=2.67m/s^2`

Acceleration of one cyclist=
`2.67m/s^2`

Acceleration of another cyclist, a'=
`(30-0)/(8)m/s^2`

Acceleration of another cyclist, a'=
`3.75m/s^2`

Yes, the acceleration of another cyclist is higher than the cyclist which accelerates from 0m/s to 8m/s.