Question

Establish the identity.

(csc0+ cot 0)(csc0- cot0) = 1

a. Multiply and write the left side expression as the difference of two squares: ?

b. The expression from the previous step is equivalent to 1 using what?
O A. Reciprocal Identity
O B. Quotient Identity
O C. Pythagorean Identity
O D. Cancellation Property
O E. Even-Odd Identity

pls help asap i can’t pass this class without passing this test

Answer 1

To answer this question, we need to first multiply the left side of the given equation and write it as the difference of two squares. This can be done by using the difference of squares formula, which states that the difference of two squares can be written as the product of the square of the sum and the square of the difference.

The left side of the given equation can be written as:

(csc0+ cot 0)(csc0- cot0)

We can then apply the difference of squares formula to this expression to get:

(csc0+ cot 0)(csc0- cot0) = (csc0+ cot 0)(csc0- cot0)

Now, we can see that this expression is equivalent to 1 using the Cancellation Property. This property states that if two numbers or expressions are equal, then their corresponding parts are also equal. In this case, since 1 = (csc0+ cot 0)(csc0- cot0), we can cancel out the corresponding parts on both sides of the equation to get 1 = 1.

Therefore, the correct answer is D. Cancellation Property.