Question

A family's cat is pregnant with 4 kittens. If the probability each kitten will be gray like the mother is 0.48 , what is the probability that at least one is not gray? If necessary, round to 4 decimal

Answer 1

The probability that at least one of the four kittens will not be gray is 0.9468 when the probability of each kitten being gray is 0.48.

Step-by-step explanation:

The question asks for the probability that at least one of the four kittens will not be gray if the probability of each kitten being gray is 0.48. To solve this, we can calculate the complementary probability that all kittens are gray and then subtract this from 1.

The probability that all four kittens are gray is (0.48)^4. Hence, the probability that at least one kitten is not gray is given by 1 - (0.48)^4.

Doing the calculation:

1. Calculate (0.48)^4: (0.48)^4 = 0.0532 (rounded to four decimal places).
2. Subtract this value from 1: 1 - 0.0532 = 0.9468.

The probability that at least one kitten is not gray is 0.9468