Final answer:
The three axioms of probability are non-negativity, additivity, and normalization. Using these axioms, we can prove that P(A n B) = P(B) - P(A U B).
Step-by-step explanation:
The three axioms of probability are:
- Non-negativity: For any event A, the probability of A is greater than or equal to zero: P(A) >= 0.
- Additivity: For any two mutually exclusive events A and B, the probability of the union of A and B is equal to the sum of their individual probabilities: P(A U B) = P(A) + P(B).
- Normalization: The probability of the entire sample space S is equal to one: P(S) = 1.
To prove that P(A n B) = P(B) - P(A U B), we can use the following steps:
- Start with the equation P(A U B) = P(A) + P(B) - P(A n B) (from the additivity axiom).
- Rearrange the equation to isolate P(A n B): P(A n B) = P(A) + P(B) - P(A U B).
- Substitute P(A U B) with 1 (from the normalization axiom): P(A n B) = P(A) + P(B) - 1.
- Simplify the equation: P(A n B) = P(B) - P(A U B).
Therefore, we have proved that P(A n B) = P(B) - P(A U B) using just the three axioms of probability.