60.1k views
5 votes
Can someone please help me with the problem? Please show your work.

Directions: Solve the following. Which is a solution to 3x^2 + 2 =0?

(√6/3)i

2/3

1

(2/3)i​

User Vincenth
by
8.5k points

1 Answer

5 votes

Final answer:

The solutions to the quadratic equation 3x^2 + 2 = 0 are x = (√(6) / 3)i and x = -(√(6) / 3)i, which are complex numbers due to the presence of the imaginary unit 'i'.

option a is the correct

Step-by-step explanation:

The student is asking how to find the solution to the quadratic equation 3x2 + 2 = 0. This type of problem is commonly solved using the quadratic formula, x = (-b ± √(b2 - 4ac)) / (2a). Applying this formula to the given equation, we substitute the coefficients a = 3, b = 0 (since there is no x term), and c = 2.

Upon substituting, we have:
x = (0 ± √(02 - 4×3×2)) / (2×3)
x = ±√(-24) / 6
x = ±√(-1)√(24) / 6

Since the square root of a negative number is an imaginary number, the solution will be in terms of 'i', where i = √(-1). Therefore, x = ±(√(24) / 6)i. Simplifying √(24) as 2√(6) gives us x = ±(2√(6) / 6)i or x = ±(√(6) / 3)i.

The correct solution is therefore x = (√(6) / 3)i and x = -(√(6) / 3)i, not the options provided in the original question. Thus, (2/3)i is not a correct solution to the equation 3x2 + 2 = 0.

User JoJoeDad
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories