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Can someone please help me with the problem? Please show your work.

Directions: Solve the following. Which is a solution to 3x^2 + 2 =0?

(√6/3)i

2/3

1

(2/3)i​

User Vincenth
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1 Answer

5 votes

Final answer:

The solutions to the quadratic equation 3x^2 + 2 = 0 are x = (√(6) / 3)i and x = -(√(6) / 3)i, which are complex numbers due to the presence of the imaginary unit 'i'.

option a is the correct

Step-by-step explanation:

The student is asking how to find the solution to the quadratic equation 3x2 + 2 = 0. This type of problem is commonly solved using the quadratic formula, x = (-b ± √(b2 - 4ac)) / (2a). Applying this formula to the given equation, we substitute the coefficients a = 3, b = 0 (since there is no x term), and c = 2.

Upon substituting, we have:
x = (0 ± √(02 - 4×3×2)) / (2×3)
x = ±√(-24) / 6
x = ±√(-1)√(24) / 6

Since the square root of a negative number is an imaginary number, the solution will be in terms of 'i', where i = √(-1). Therefore, x = ±(√(24) / 6)i. Simplifying √(24) as 2√(6) gives us x = ±(2√(6) / 6)i or x = ±(√(6) / 3)i.

The correct solution is therefore x = (√(6) / 3)i and x = -(√(6) / 3)i, not the options provided in the original question. Thus, (2/3)i is not a correct solution to the equation 3x2 + 2 = 0.

User JoJoeDad
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