Final answer:
The minimum number of moles of O2 needed to completely react with 16 moles of NH3 is 20 moles.
Step-by-step explanation:
In order to determine the minimum number of moles of O2 needed to completely react with 16 moles of NH3, we need to look at the balanced equation for the reaction:
4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(l)
From the equation, we can see that for every 4 moles of NH3, we need 5 moles of O2.
Therefore, we can set up a proportion to find the number of moles of O2 needed:
(5 moles O2 / 4 moles NH3) = (x moles O2 / 16 moles NH3)
Cross multiplying, we get:
x moles O2 = (5 moles O2 / 4 moles NH3) * 16 moles NH3
= 20 moles O2
Therefore, the minimum number of moles of O2 needed to completely react with 16 moles of NH3 is 20 moles.