192k views
3 votes
Using the genetic code table, what amino acid sequence will be generated from the given mRNA sequence 5' AUG-UCU-UCG-UUA-UCC-UUG 3'?

a) Methionine - Serine - Serine - Leucine - Serine - Leucine
b) Methionine - Serine - Serine - Leucine - Proline - Leucine
c) Methionine - Serine - Serine - Leucine - Serine - Valine
d) Methionine - Serine - Serine - Leucine - Proline - Valine

User Peterhil
by
7.6k points

1 Answer

1 vote

Final answer:

The mRNA sequence 5' AUG-UCU-UCG-UUA-UCC-UUG 3' translates to the amino acid sequence Methionine - Serine - Serine - Leucine - Serine - Leucine, corresponding to option (a).

Step-by-step explanation:

The amino acid sequence generated from the given mRNA sequence 5' AUG-UCU-UCG-UUA-UCC-UUG 3' can be determined by using a genetic code table, which matches each set of three nucleotides (a codon) to a corresponding amino acid.

By consulting the genetic code table:

  • AUG codes for Methionine (Met).
  • UCU and UCG code for Serine (Ser).
  • UUA and UUG code for Leucine (Leu).
  • UCC codes for Serine (Ser) as well.

Therefore, we get the following amino acid sequence: Methionine - Serine - Serine - Leucine - Serine - Leucine, which corresponds to choice (a).

User Albert Romkes
by
7.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories