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Using the genetic code table, what amino acid sequence will be generated from the given mRNA sequence 5' AUG-UCU-UCG-UUA-UCC-UUG 3'?

a) Methionine - Serine - Serine - Leucine - Serine - Leucine
b) Methionine - Serine - Serine - Leucine - Proline - Leucine
c) Methionine - Serine - Serine - Leucine - Serine - Valine
d) Methionine - Serine - Serine - Leucine - Proline - Valine

User Peterhil
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1 Answer

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Final answer:

The mRNA sequence 5' AUG-UCU-UCG-UUA-UCC-UUG 3' translates to the amino acid sequence Methionine - Serine - Serine - Leucine - Serine - Leucine, corresponding to option (a).

Step-by-step explanation:

The amino acid sequence generated from the given mRNA sequence 5' AUG-UCU-UCG-UUA-UCC-UUG 3' can be determined by using a genetic code table, which matches each set of three nucleotides (a codon) to a corresponding amino acid.

By consulting the genetic code table:

  • AUG codes for Methionine (Met).
  • UCU and UCG code for Serine (Ser).
  • UUA and UUG code for Leucine (Leu).
  • UCC codes for Serine (Ser) as well.

Therefore, we get the following amino acid sequence: Methionine - Serine - Serine - Leucine - Serine - Leucine, which corresponds to choice (a).

User Albert Romkes
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