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Write the equilibrium constant expressions for the following reactions.
BaCO3(s)⇔BaO(s)+CO2(g)

1 Answer

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Final answer:

The equilibrium constant expression for the reaction BaCO3(s) ⇔ BaO(s) + CO2(g) is given by Kp = P(CO2), as only gaseous components are included in the expression. Solids like BaCO3 and BaO do not appear in the equilibrium constant expression.

Step-by-step explanation:

Writing Equilibrium Constant Expressions

The reaction BaCO3(s) ⇔ BaO(s) + CO2(g) involves a solid reactant breaking down into another solid and a gaseous product. When writing an equilibrium constant expression for a reaction, it is important to remember that only the concentrations of gases and aqueous solutions are included. Solids and liquids do not appear in the expression because their concentration does not change in a closed system.

To write the equilibrium constant expression (Kp) for the given reaction in terms of partial pressure, we only include the gaseous CO2. The expression would be:

Kp = P(CO2)

Since BaCO3 and BaO are both solids, they do not appear in the expression.

Other Equilibrium Expressions:

  • For N2(g) + 3 H2(g) ⇔ 2 NH3(g), the Kc expression would be: Kc = [NH3]^2 / ([N2] · [H2]^3)
  • For CO(g) + O2(g) ⇔ CO2(g), the equilibrium constant expression is: Kc = [CO2] / ([CO] · [O2])
  • For 2 CO2(g) ⇔ 2 CO(g) + O2(g), the expression is: Kc = ([CO]^2 · [O2]) / [CO2]^2

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