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the width of javier's rectangular math classroom is 7 feet less than 3 times its length. the perimeter of the classroom is 82 feet. what is the lenth of th e classroom

User Cibeli
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Final answer:

After translating the problem's information into equations, we can find that the length of Javier's rectangular math classroom is 12 feet.

Step-by-step explanation:

To determine the length of Javier's math classroom, we first need to translate the given information into mathematical expressions. Let's define the length of the room as L and the width as W. The problem gives us two pieces of information:

  • The width is 7 feet less than three times its length: W = 3L - 7.
  • The perimeter of the classroom is 82 feet: P = 2L + 2W = 82.

Plugging the expression for W into the perimeter equation gives us:

2L + 2(3L - 7) = 82

Simplifying:

2L + 6L - 14 = 82

8L - 14 = 82

Adding 14 to both sides of the equation yields:

8L = 96

Dividing both sides by 8 gives us:

L = 12

Therefore, the length of the classroom is 12 feet.

User Wyatt
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