Final answer:
After translating the problem's information into equations, we can find that the length of Javier's rectangular math classroom is 12 feet.
Step-by-step explanation:
To determine the length of Javier's math classroom, we first need to translate the given information into mathematical expressions. Let's define the length of the room as L and the width as W. The problem gives us two pieces of information:
- The width is 7 feet less than three times its length: W = 3L - 7.
- The perimeter of the classroom is 82 feet: P = 2L + 2W = 82.
Plugging the expression for W into the perimeter equation gives us:
2L + 2(3L - 7) = 82
Simplifying:
2L + 6L - 14 = 82
8L - 14 = 82
Adding 14 to both sides of the equation yields:
8L = 96
Dividing both sides by 8 gives us:
L = 12
Therefore, the length of the classroom is 12 feet.