222k views
16 votes
A person invests 5000 dollars in a bank. The bank pays 5.25% interest compounded semi-annually. To the nearest tenth of a year, how long must the person leave the money in the bank until it reaches 10200 dollars?

User Bnrdo
by
3.4k points

2 Answers

8 votes

Final answer:

To find out how long it takes for $5,000 to grow to $10,200 with a 5.25% interest rate compounded semi-annually, we can use the formula A = P(1 + r/n)^(nt). Solving this equation, we find that the time required is approximately 8.3 years.

Step-by-step explanation:

To find out how long it takes for the money to reach $10,200, we need to determine the time required to grow from $5,000 to $10,200 with a 5.25% interest rate compounded semi-annually.

We can use the formula:

A = P(1 + r/n)^(nt)

where:

  • A = future value
  • P = principal (initial investment)
  • r = annual interest rate (as a decimal)
  • n = number of compounding periods per year
  • t = number of years

In this case, P = $5,000, A = $10,200, r = 5.25% = 0.0525, and n = 2 (semi-annual compounding).

Substituting these values into the formula, we get:

$10,200 = $5,000(1 + 0.0525/2)^(2t)

Dividing both sides by $5,000, we get:

2.04 = (1.02625)^(2t)

Taking the logarithm of both sides, we get:

log(2.04) = log(1.02625)^(2t)

Using the logarithm properties, we can simplify:

2t = log(2.04) / log(1.02625)

Finally, solving for t, we get:

t = (log(2.04) / log(1.02625)) / 2

Calculating the right-hand side of the equation gives us approximately 8.3. Therefore, the person must leave the money in the bank for 8.3 years (to the nearest tenth of a year) to reach $10,200.

User Damien Doumer
by
3.5k points
12 votes

Answer:13.8

Step-by-step explanation:

User Jalal Sordo
by
3.3k points