Final answer:
A 360° counterclockwise rotation of a triangle around the origin leaves the triangle unchanged. Therefore, the vertices of the triangle W'P'B' after rotation are W' (6,-5), P' (6,-1), B' (3,-6), the same as the original triangle W (6,-5), P (6,-1), B (3,-6).
Step-by-step explanation:
The question involves a geometrical transformation, specifically a rotation of a triangle in the coordinate plane. The coordinates of the vertices of the given triangle are W (6,-5), P (6,-1), B (3,-6).
When a figure is rotated 360° counterclockwise around the origin, each point of the figure comes back to its original position.
Therefore, the coordinates of the vertices of triangle W'P'B' after a 360° rotation would remain unchanged and be W' (6,-5), P' (6,-1), B' (3,-6).