Question

Two planes start from the same point and fly in opposite directions. The fist plane is flying 25 mph slower than the second plane. In 3 h, the planes are 705 mi apart. Find the rate of each plane. a) 105 mph and 130 mph

b) 130 mph and 105 mph
c) 155 mph and 130 mph
d) 130 mph and 155 mph

Answer 1

The rate of the first plane is 105 mph and the rate of the second plane is 130 mph. The correct answer is option b) 130 mph and 105 mph.

Step-by-step explanation:

The correct answer is option b) 130 mph and 105 mph.

Let's denote the rate of the second plane as x mph. Since the first plane is flying 25 mph slower than the second plane, the rate of the first plane is x - 25 mph.

According to the given information, the planes are 705 mi apart after 3 hours. This means that the total distance covered by both planes is 705 mi.

Using the formula distance = rate × time, we can set up the following equation:

(x mph × 3 h) + ((x - 25) mph × 3 h) = 705 mi

Simplifying the equation:

3x + 3(x - 25) = 705

3x + 3x - 75 = 705

6x - 75 = 705

6x = 780

x = 130

Substituting the value of x back into the equation, we can find the rate of the first plane:

x - 25 = 130 - 25 = 105 mph

Therefore, the rate of the first plane is 105 mph and the rate of the second plane is 130 mph.