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A gold ring has a mass of 15,37 g. If this ring is pure gold (density - 16/1g/mL), what would the volume of the ring be?

a. 15.37 mL
b. 0.963 mL
c. 1.37 mL
d. 2.37 mL

1 Answer

4 votes

Final answer:

The correct answer is 0.796 mL, calculated by dividing the mass of 15.37 g by the density of gold (19.3 g/mL). The options provided in the question do not match this value; therefore, there may be a typo in the given density.

Step-by-step explanation:

The correct answer is option b. 0.963 mL. To find the volume of the gold ring, we use the density formula which is density (d) = mass (m) / volume (V). The mass of the ring is given as 15.37 g.

Given that the density of pure gold is roughly 19.3 g/mL, we can rearrange the formula to solve for volume: V = m / d. Therefore, the volume of gold that has a mass of 15.37 g is V = 15.37 g / 19.3 g/mL which equals approximately 0.796 mL.

However, the information provided used 16 g/mL (which seems to be a typo because the accurate density of gold is 19.3 g/mL). Using the correct density value gives us the right answer of 0.796 mL, which is not one of the options provided.

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