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How many atoms would you find in 3.60 g of Boron?

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Answer:

1.8 * 10^24 atoms

Step-by-step explanation:

n = M(B) / m = 10.8 / 3.60 = 3 mol

N = n * Na = 3 * 6*10^23 = 1.8 * 10^24 atoms

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