97.6k views
3 votes
The temperature at which volume of a given mass of a gas will become double as compared to volume at 10degree centigrade?

1 Answer

3 votes

Final answer:

To determine the temperature at which the volume of a gas doubles compared to its volume at 10°C, Charles's law is applied where the volume of a gas is directly proportional to its temperature in Kelvin when pressure is constant.

Step-by-step explanation:

The student is asking about a concept in Physics, specifically related to Charles's law, which is a gas law where the volume of a gas is directly proportional to its temperature when pressure is kept constant. To find the temperature at which the volume of a given mass of gas doubles compared to its volume at 10°C, one would need to use Charles's law formula: V1/T1 = V2/T2, where V1 is the initial volume, V2 is the final volume, T1 is the initial temperature, and T2 is the final temperature.

Since the volume is doubling, V2 = 2 * V1. The initial temperature is given in degrees Celsius, so it must first be converted to Kelvin by adding 273.15, resulting in T1 = 283.15 K. Substituting the values into the formula and solving for T2 gives us the final temperature in Kelvin.

According to Gay-Lussac's law, for a given amount of gas held at constant volume, the pressure is proportional to the absolute temperature. Mathematically, if the temperature doubles, the pressure doubles. Therefore, if the volume of a given mass of gas is to become double as compared to its volume at 10 degrees Celsius, the temperature must also double.

User Tobifasc
by
8.4k points

Related questions

asked Jan 17, 2021 111k views
Lingling asked Jan 17, 2021
by Lingling
7.2k points
1 answer
1 vote
111k views
asked Jan 5, 2021 67.3k views
Omar Abid asked Jan 5, 2021
by Omar Abid
6.9k points
1 answer
0 votes
67.3k views