Question

HURRY PLEASE

If 12 grams of sodium reacts with 16 grams of chlorine, how much sodium chloride is Formed?
A. 4 g
B. 12 g
C. 28 g
D. 30 g

Answer 1

6.576 g NaCl

Step-by-step explanation:

2Na + Cl2 --> 2 NaCl

Step 1: Find out moles of Na and Cl to determine the limiting reactant:

moles Na = 12/23 = 0.52 moles Na

moles Cl2 = 16/71=0.225 moles Cl2

ratio Na:Cl is 2.3:1 so Cl is the limiting reactant.

Step 2: How many moles of NaCl are formed:

moles NaCl = moles Cl2 x (1 mol NaCl/2 moles Cl2) = 0.225/2 = 0.1125 moles NaCl

Step 3:

mass NaCl = moles NaCl x MM NaCl = 0.1125 x 58.45 = 6.576 g NaCl