Final answer:
The schedules belong to different classes based on view-serializable and conflict-serializable criteria.
Step-by-step explanation:
a. The given schedule Tu W(X) T2: R(X) W(X) W(X) is not view-serializable because the order of operations does not match the order of precedence of transactions. It is also not conflict-serializable because there is a conflict between T2 and T1 for the write operation on X.
b. The given schedule TI: R(Y) T2: W(X) R(X) R(Y) is view-serializable because it follows the precedence of T1 and T2. It is also conflict-serializable because there are no conflicting operations between the transactions.
c. The given schedule TI: REX) T2: R(Y) W(X) T3: R(Y) R(X) W(X) is not view-serializable because there is a conflict between T1 and T3 for the write operation on X. It is also not conflict-serializable because there is a conflict between T1 and T3 for the read operation on X.
d. The given schedule TI: R(X) R(Y) W(X) T2 T3 R(Y) R(Y) W(Y) is not view-serializable because there is a conflict between T1 and T3 for the write operation on X. It is also not conflict-serializable because there is a conflict between T1 and T3 for the read operation on Y.
e. The given schedule Ti Roxi Wixi W X) commit commit commit 13: WEX) is view-serializable because it follows the precedence of T1 and T3. It is also conflict-serializable because there are no conflicting operations between the transactions.