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Determine the moles of OH⁻ in a 24.14 ml sample of 0.4998 M NaOH.

a) 0.012 moles
b) 0.024 moles
c) 0.036 moles
d) 0.048 moles

User Joe Bobby
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1 Answer

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Final answer:

To calculate moles of OH⁻ in 24.14 ml of 0.4998 M NaOH, convert ml to L, multiply by molarity, leading to approximately 0.012 moles of OH⁻, which is answer option a).

Step-by-step explanation:

To determine the moles of OH⁻ in a 24.14 ml sample of 0.4998 M NaOH, we use the formula:

moles of NaOH = Volume (L) × Molarity (M)

First, we convert the volume from milliliters to liters:

24.14 ml × (1 L/1000 ml) = 0.02414 L

Next, we calculate the moles of NaOH:

moles of NaOH = 0.02414 L × 0.4998 M = 0.012058292 mol

Since NaOH dissociates completely in water to give one mole of OH⁻ for each mole of NaOH:

moles of OH⁻ = moles of NaOH = 0.012058292 mol

The closest answer to this value is option a) 0.012 moles.

User Shabarinath Volam
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