Final answer:
To calculate moles of OH⁻ in 24.14 ml of 0.4998 M NaOH, convert ml to L, multiply by molarity, leading to approximately 0.012 moles of OH⁻, which is answer option a).
Step-by-step explanation:
To determine the moles of OH⁻ in a 24.14 ml sample of 0.4998 M NaOH, we use the formula:
moles of NaOH = Volume (L) × Molarity (M)
First, we convert the volume from milliliters to liters:
24.14 ml × (1 L/1000 ml) = 0.02414 L
Next, we calculate the moles of NaOH:
moles of NaOH = 0.02414 L × 0.4998 M = 0.012058292 mol
Since NaOH dissociates completely in water to give one mole of OH⁻ for each mole of NaOH:
moles of OH⁻ = moles of NaOH = 0.012058292 mol
The closest answer to this value is option a) 0.012 moles.