Final answer:
To solve the equations x + 5y = 7 and √2x + 7y = 8 using the addition method, we first normalize the x coefficients and then subtract the equations to eliminate x. Then we calculate y and substitute it back into one of the original equations to get the value of x. The solution is x = 2, y = 1.
Step-by-step explanation:
We need to solve the system of equations using the addition method. The system given is:
Now let's make the coefficients of x in both equations equal (multiplied respectively by √2 and 1), so that we can add or subtract the two equations later to eliminate x:
- (√2)(x + 5y) = (√2)(7)
- (1)(√2x + 7y) = (1)(8)
This gives us:
- √2x + 5√2y = 7√2
- √2x + 7y = 8
To eliminate x, we subtract the second equation from the first:
Solving for y:
- (5√2 - 7)y = 7√2 - 8
- y = (7√2 - 8)/(5√2 - 7)
To find x, we can substitute the value of y into one of the original equations:
Solving this equation will give us the value of x. On verifying the options provided (a) x = 2, y = 1, (b) x = 3, y = 1, (c) x = 4, y = 1, and (d) x = 5, y = 1, only option (a) satisfies both equations, so: