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Find the center of the circle represented by the equation x^2-6x y^2 10y 18=0

A) (3, 5)
B) (3, -5)
C) (-3, 5)
D) (-3, -5)

User Lisseth
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8.3k points

1 Answer

3 votes

Final answer:

The center of the circle represented by the equation
x^2-6x+y^2-10y+18=0 is (3, -5).

Step-by-step explanation:

The equation of the circle is x² - 6x + y² - 10y + 18 = 0. To find the center of the circle, we need to rewrite the equation in a specific form: (x - h)² + (y - k)² = r². Comparing this form to the given equation, we can identify the center as (h, k), which is the opposite sign of the coefficient of x and y. In this case, the center is (3, -5), so the correct answer is B.

User Lulop
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8.1k points

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