Question

For the quadratic function, find the x-value of the vertex (axis of symmetry). y=x²−2x−7?

a) x=1
b) x=−1
c) x=2
d) x=−2

Answer 1

The x-value of the vertex of the quadratic function y=x²-2x-7 is x=1, determined by using the formula x=-b/(2a) with coefficients a=1 and b=-2.

Step-by-step explanation:

The x-value of the vertex for a quadratic function is found using the formula x = -b/(2a), where a and b are the coefficients from the quadratic equation in the form ax² + bx + c = 0. For the given quadratic function y = x² - 2x - 7, we have a = 1 and b = -2. Applying the formula, we get x = -(-2)/(2*1) = 2/(2) = 1. Hence, the x-value of the vertex (axis of symmetry) for the given quadratic equation is x = 1.To find the x-value of the vertex (axis of symmetry) of the quadratic function y=x²−2x−7, we can use the formula x = -b/(2a), where a is the coefficient of x² and b is the coefficient of x. In this case, a=1 and b=-2.

Substituting the values into the formula, we get x = -(-2)/(2*1) = 2/2 = 1. So the x-value of the vertex is 1.