Answer: x=4 y=-1 z=3
Explanation:
x+y+z=6 (1)
x+y=z (2)
1+z=x (3)
1) Subtract equation (2) from equation (1):
z=6-z
z+z=6-z+z
2z=6
Divide both parts of the equation by 2:
z=3
2) Subtract the value of z=3 into equation (3):
1+3=x
4=x
Thus, x=4
3) Subtract the value of z=3 and x=4 into equation (1):
4+y+3=6
7+y=6
7+y-7=6-7
y=-1