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What is the equation of the line passing through points (-1,3) and (2,4)?

a) y = x + 2 b) y = 1 / 3 x + 10 / 3 c) y = 3x + 2 d) y = 1 / 3 x + 11 / 3

User Wfjm
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1 Answer

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Final answer:

To find the equation of the line passing through the points (-1,3) and (2,4), we first calculate the slope using the formula. Then, we use the point-slope form of a linear equation to find the equation of the line. The equation of the line passing through the given points is y = 1 / 3 x + 10 / 3.

Step-by-step explanation:

To find the equation of the line passing through the points (-1,3) and (2,4), we first need to find the slope of the line. The slope can be found using the formula m = (y2-y1)/(x2-x1), where (x1,y1) and (x2,y2) are the coordinates of the two points.

Using the formula, we have m = (4 - 3) / (2 - (-1)) = 1 / 3.

Next, we can use the point-slope form of a linear equation y - y1 = m(x - x1), where (x1,y1) is one of the points on the line.

Using the point (-1,3), we have y - 3 = 1 / 3(x - (-1)). Simplifying this equation, we get y - 3 = 1 / 3(x + 1). Rearranging the equation to slope-intercept form, we have y = 1 / 3 x + 1 / 3 + 9 / 3 = 1 / 3 x + 10 / 3.

Therefore, the equation of the line passing through the points (-1,3) and (2,4) is y = 1 / 3 x + 10 / 3.

User Kevin Murvie
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