Final answer:
The vertex of the quadratic equation -2(x-5)^2+8 is (5, 8), found by identifying the values of 'h' and 'k' in the vertex form of a quadratic equation.
Step-by-step explanation:
To find the vertex of the quadratic equation given in the format -2(x-5)^2+8, we can use the fact that this equation is already in vertex form, which is y = a(x-h)^2 + k, where (h, k) is the vertex of the parabola.
For the equation -2(x-5)^2+8, the value of 'h' is 5 and the value of 'k' is 8, making the vertex (5, 8).
It's important to note that 'a' represents the direction of the parabola; since 'a' (-2) is negative, the parabola opens downwards.