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Find the value of c so that (x+3) is a factor of the polynomial p(x). p(x)=x^3-4x^2+cx+33

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5 votes

Answer:

The value of c is -10.

Explanation:

Since (x+3) is a factor of the polynomial p(x).

We have that:

x + 3 = 0 -> x = -3

So p(-3) = 0

Then


p(x) = x^3 - 4x^2 + cx + 33


(-3)^3 - 4(-3)^2 - 3c + 33 = 0


-27 - 36 - 3c + 33 = 0


3c = -30


c = -(30)/(3)


c = -10

The value of c is -10.

User PrasadK
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